rob-matthews_60b4ebc3487b4
rob-matthews_60b4ebc3487b4
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(x+2/x+1)´ = [(x+2)´(x+1)+(x+2)(x+1)´]/(x+1)^2 = [1*(x+1)+1*(x+2)]/(x+2)^2 = (2x + 3)/[x^2 + 2x + 1] Porque (1)´=0 Derivada da constante é ZERO.