rob-anderson_60a9e0f91235a
rob-anderson_60a9e0f91235a
About
- Username
- rob-anderson_60a9e0f91235a
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
Bueno del NH3 es =14+3(1)=17u.m.a , luego H20 =2(1)+16=18 U.M.A, CH4 = 12 +4(1)=16U.M.A , LUEGO HCl =1+35,5 =36.5 u.m.a y KOH = 39 +16+1=56u.m.a espero haberte ayudado