rebecca-davis_60ac1a0b67f4a
rebecca-davis_60ac1a0b67f4a
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DEsenvolvendo a inequação: x² - 3x > 0 Delta = b² - 4.a.c Delta = (-3)² - 4.1.0 Delta = 9 x = (-b +/- (raiz)Delta)/2a x = (3 +/- 3)/2 x' = (3 + 3)/2 = 6/2 = 3 x" = (3 - 3)/2 = 0/2 = 0 As raÃzes são 0 e 3. Agora, temos…