Comments

• For differentiating the function y = (sinx)^(2sinx) first take Ln on both sides, applying the rules applicable to Ln, getting: Ln (y) = 2sinx*Ln(sinx). Now differentiate both sides w.r.t. x, using the product formula on R.H.S. 1/y*dy/dx =…

  in derivatives dy/dx of y=(sinx)^(2sinx)? Comment by quidwai May 2021
• For differentiating the function y = (sinx)^(2sinx) first take Ln on both sides, applying the rules applicable to Ln, getting: Ln (y) = 2sinx*Ln(sinx). Now differentiate both sides w.r.t. x, using the product formula on R.H.S. 1/y*dy/dx =…

  in derivatives dy/dx of y=(sinx)^(2sinx)? Comment by quidwai May 2021