puzzling
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First weighing: Split the 27 balls into groups of 9, 9, 9. Put 9 balls on one side, 9 on the other. If one side of the scale goes down, the heavy ball is in that group. If they balance, the heavy ball is in the group you didn't weigh. Second …
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Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
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Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
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Let n be the amount of sales (in thousands) of best grade siding. $40k * 20% = $8k $50k * 30% = $15k n * 60% = 0.6n Total profit will be 8 + 15 + 0.6n Total sales will be 40 + 50 + n The profit on the siding should equal 50% of the total…
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The mean is given as 78.3 You want all numbers that are within 1 standard deviation (which is also given as 10.3). So the smallest possible number is: 78.3 - 10.3 = 68 And the largest possible number is: 78.3 + 10.3 = 88.6 Answer: Any…
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The mean is given as 78.3 You want all numbers that are within 1 standard deviation (which is also given as 10.3). So the smallest possible number is: 78.3 - 10.3 = 68 And the largest possible number is: 78.3 + 10.3 = 88.6 Answer: Any…
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Let V be the volume (in liters) Let P be the pressure (in kilopascals) If they varied *directly* then we would say that the volume (V) was equal to a constant (k) *times* the pressure (P). But they vary *inversely*. So the volume (V) is equal…
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You can use the ^ symbol to represent "to the power of": 5^3 x 5 x 5^4 When you multiply numbers with the same base, you can *add* the exponents. 3 + 1 + 4 = 8 (Remember that 5 is the same as 5^1) So this is equivalent to: …
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Let x be the width of the garden in feet (on the fenced side). Let 3000/x be the length of the garden in feet. The cost of surrounding the lot will be: $14 for one width $22 for two lengths and one width A function for the cost for a given …
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Let x be the width of the garden in feet (on the fenced side). Let 3000/x be the length of the garden in feet. The cost of surrounding the lot will be: $14 for one width $22 for two lengths and one width A function for the cost for a given …
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You would need to know something about the shape of the tanks. Assuming they were cylinders, for example, you'd need the radius to figure the area of the base. liters and milliliters are measurements of volume. meters and millimeters are measur…
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You would need to know something about the shape of the tanks. Assuming they were cylinders, for example, you'd need the radius to figure the area of the base. liters and milliliters are measurements of volume. meters and millimeters are measur…
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Let x be the width of the garden in feet (on the fenced side). Let 3000/x be the length of the garden in feet. The cost of surrounding the lot will be: $14 for one width $22 for two lengths and one width A function for the cost for a given …
-
You can use the ^ symbol to represent "to the power of": 5^3 x 5 x 5^4 When you multiply numbers with the same base, you can *add* the exponents. 3 + 1 + 4 = 8 (Remember that 5 is the same as 5^1) So this is equivalent to: …
-
You can use the ^ symbol to represent "to the power of": 5^3 x 5 x 5^4 When you multiply numbers with the same base, you can *add* the exponents. 3 + 1 + 4 = 8 (Remember that 5 is the same as 5^1) So this is equivalent to: …
-
Let V be the volume (in liters) Let P be the pressure (in kilopascals) If they varied *directly* then we would say that the volume (V) was equal to a constant (k) *times* the pressure (P). But they vary *inversely*. So the volume (V) is equal…
-
The mean is given as 78.3 You want all numbers that are within 1 standard deviation (which is also given as 10.3). So the smallest possible number is: 78.3 - 10.3 = 68 And the largest possible number is: 78.3 + 10.3 = 88.6 Answer: Any…
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Let n be the amount of sales (in thousands) of best grade siding. $40k * 20% = $8k $50k * 30% = $15k n * 60% = 0.6n Total profit will be 8 + 15 + 0.6n Total sales will be 40 + 50 + n The profit on the siding should equal 50% of the total…
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Let n be the amount of sales (in thousands) of best grade siding. $40k * 20% = $8k $50k * 30% = $15k n * 60% = 0.6n Total profit will be 8 + 15 + 0.6n Total sales will be 40 + 50 + n The profit on the siding should equal 50% of the total…
-
Let n be the amount of sales (in thousands) of best grade siding. $40k * 20% = $8k $50k * 30% = $15k n * 60% = 0.6n Total profit will be 8 + 15 + 0.6n Total sales will be 40 + 50 + n The profit on the siding should equal 50% of the total…
-
Let n be the amount of sales (in thousands) of best grade siding. $40k * 20% = $8k $50k * 30% = $15k n * 60% = 0.6n Total profit will be 8 + 15 + 0.6n Total sales will be 40 + 50 + n The profit on the siding should equal 50% of the total…
-
Let n be the amount of sales (in thousands) of best grade siding. $40k * 20% = $8k $50k * 30% = $15k n * 60% = 0.6n Total profit will be 8 + 15 + 0.6n Total sales will be 40 + 50 + n The profit on the siding should equal 50% of the total…
-
Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
-
Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
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Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
-
Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
-
Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
-
Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
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Algebraically: Let B = amount invested in bonds Let S = amount invested in savings We know that: B + S = 400,000 0.04B = 0.01S Take the bottom equation and multiply both sides by 100 to remove the decimals. 4B = S Now substitute S = 4B…
-
First weighing: Split the 27 balls into groups of 9, 9, 9. Put 9 balls on one side, 9 on the other. If one side of the scale goes down, the heavy ball is in that group. If they balance, the heavy ball is in the group you didn't weigh. Second …