Comments

• 1. Just multiply across and reduce. (15/7a)(14/3b) = 210/21ab = 10ab 2. Distribute the numbers outside of the parentheses. 2(3r+4)=5(-2r-8) (2*3r)+(2*4) = (5*-2r)-(5*8) 6r+8=-10r-40 16r = -48 r = -3 3. Same thing as #2. 2(3r+1)+6=5(-2r-…

  in alegbra math problem? Comment by pinkpugsy May 2021
• 1. Just multiply across and reduce. (15/7a)(14/3b) = 210/21ab = 10ab 2. Distribute the numbers outside of the parentheses. 2(3r+4)=5(-2r-8) (2*3r)+(2*4) = (5*-2r)-(5*8) 6r+8=-10r-40 16r = -48 r = -3 3. Same thing as #2. 2(3r+1)+6=5(-2r-…

  in alegbra math problem? Comment by pinkpugsy May 2021