pete-phillips_60ba0eeea318f
pete-phillips_60ba0eeea318f
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Boa noite! d = n(n-3) / 2 Se d = 35, temos que: 35 = n(n-3) / 2 70 = n² - 3n n² - 3n - 70 = 0 Resolvendo por Bháskara: ∆ = b² - 4.a.c ∆ = (-3)² - 4.1.-70 ∆ = 9 + 280 ∆ = 289 Enfim: n = (- b ± √∆ ) / 2.a n = (- (-3) ± √289 …