patrick-marshall_60b7bee1f3c18
patrick-marshall_60b7bee1f3c18
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f(x) = x^2-6x+11 First we could make the expression x^2-6x right into a applicable sq. binomial The formula to get the consistent is (B/2)^2 so because it is (-6/2)^2 = 9 f(x) = x^2 - 6x + 9 - 9 + 11 ^-- you are able to subtract the 9 besides to mai…