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• The factors are: [x - (-1-127^0.5)/12] and [x - (-1+127^0.5)/12] or [x + 1.0225] and [x - 0.8558] To factorise this expression, you can use the solution formula for quadratic equation, i.e. x = [-b +/- (b^2 - 4ac)^0.5]/(2a) T…

  in How do you factor 24x^2 + 4x - 21? Comment by orhhai June 2021
• The factors are: [x - (-1-127^0.5)/12] and [x - (-1+127^0.5)/12] or [x + 1.0225] and [x - 0.8558] To factorise this expression, you can use the solution formula for quadratic equation, i.e. x = [-b +/- (b^2 - 4ac)^0.5]/(2a) T…

  in How do you factor 24x^2 + 4x - 21? Comment by orhhai May 2021
• The factors are: [x - (-1-127^0.5)/12] and [x - (-1+127^0.5)/12] or [x + 1.0225] and [x - 0.8558] To factorise this expression, you can use the solution formula for quadratic equation, i.e. x = [-b +/- (b^2 - 4ac)^0.5]/(2a) T…

  in How do you factor 24x^2 + 4x - 21? Comment by orhhai May 2021