ooorah
ooorah
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Since it's a school computer and they don't give you full rights over it, I would assume that they have some sort of tech support thing for this. You can possibly even get a temporary computer to work on while they fix it. Just remember to get all y…
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It's been awhile since I've seen this kind of notation, so I'm going to assume that ' denotes the inverse function. As in g'(g(x)) = g(g'(x)) = x. I believe then that the answer is no. Again, if I remember correctly, (f∘g)(x) = f(g(x)). You can a…
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I'll assume this is (1/4)x+(3/2)x = 7 You need to get a common denominator. In this case just multiply the right term by 2/2: (1/4)x+(6/4)x = 7 Add like terms: (7/4)x = 7 Divide both sides by 7/4: x = 4
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I'll assume this is (1/4)x+(3/2)x = 7 You need to get a common denominator. In this case just multiply the right term by 2/2: (1/4)x+(6/4)x = 7 Add like terms: (7/4)x = 7 Divide both sides by 7/4: x = 4
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I'll assume this is (1/4)x+(3/2)x = 7 You need to get a common denominator. In this case just multiply the right term by 2/2: (1/4)x+(6/4)x = 7 Add like terms: (7/4)x = 7 Divide both sides by 7/4: x = 4
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It's been awhile since I've seen this kind of notation, so I'm going to assume that ' denotes the inverse function. As in g'(g(x)) = g(g'(x)) = x. I believe then that the answer is no. Again, if I remember correctly, (f∘g)(x) = f(g(x)). You can a…
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It's been awhile since I've seen this kind of notation, so I'm going to assume that ' denotes the inverse function. As in g'(g(x)) = g(g'(x)) = x. I believe then that the answer is no. Again, if I remember correctly, (f∘g)(x) = f(g(x)). You can a…