northstar
northstar
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The number is 135. _________ Let the number be abc. We have: a + b + c = 9 a = b/3 (100c + 10b + a) - (100a + 10b + c) = 396 From the second equation: a = b/3 b = 3a From the third equation: (100c + 10b + a) - (100a + 10b + c) =…
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The number is 135. _________ Let the number be abc. We have: a + b + c = 9 a = b/3 (100c + 10b + a) - (100a + 10b + c) = 396 From the second equation: a = b/3 b = 3a From the third equation: (100c + 10b + a) - (100a + 10b + c) =…
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It is possible to earn every number of the form: 5x is possible starting with 0 5x + 7 = 5(x + 1) + 2 starting with 7 5x + 2*7 = 5x + 14 = 5(x + 2) + 4 starting with 14 5x + 3*7 = 5x + 21 = 5(x + 4) + 1 starting with 21 5x + 4*7 = 5x + 28 = 5…
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It is possible to earn every number of the form: 5x is possible starting with 0 5x + 7 = 5(x + 1) + 2 starting with 7 5x + 2*7 = 5x + 14 = 5(x + 2) + 4 starting with 14 5x + 3*7 = 5x + 21 = 5(x + 4) + 1 starting with 21 5x + 4*7 = 5x + 28 = 5…
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We have an inverted parabola that can be described by the equation: y = ax² + 12 We have three points on the parabola: (0, 12); (-4, 10); and (4,10). Plug in the third point and solve for a. y = ax² + 12 10 = a(4²) + 12 -2 = 16a …
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We have an inverted parabola that can be described by the equation: y = ax² + 12 We have three points on the parabola: (0, 12); (-4, 10); and (4,10). Plug in the third point and solve for a. y = ax² + 12 10 = a(4²) + 12 -2 = 16a …
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It is possible to earn every number of the form: 5x is possible starting with 0 5x + 7 = 5(x + 1) + 2 starting with 7 5x + 2*7 = 5x + 14 = 5(x + 2) + 4 starting with 14 5x + 3*7 = 5x + 21 = 5(x + 4) + 1 starting with 21 5x + 4*7 = 5x + 28 = 5…
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The number is 135. _________ Let the number be abc. We have: a + b + c = 9 a = b/3 (100c + 10b + a) - (100a + 10b + c) = 396 From the second equation: a = b/3 b = 3a From the third equation: (100c + 10b + a) - (100a + 10b + c) =…