no-mythology
no-mythology
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You can solve the first equation for y² in terms of x² (or the other way around) and reduce the system to a quadratic in a single variable. y² = 9 - x². Put this into the second equation x²/64 + (9 - x²)/16 = 1. Multiply through by 64…
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You can solve the first equation for y² in terms of x² (or the other way around) and reduce the system to a quadratic in a single variable. y² = 9 - x². Put this into the second equation x²/64 + (9 - x²)/16 = 1. Multiply through by 64…
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If the integrand is supposed to be 5/x² plus 1, then the Fundamental Theorem of Calculus does not apply. The integrand isn't continuous on [-1, 1]. The integral is divergent. The principal value integral exists, but that's not an application of the …
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If the integrand is supposed to be 5/x² plus 1, then the Fundamental Theorem of Calculus does not apply. The integrand isn't continuous on [-1, 1]. The integral is divergent. The principal value integral exists, but that's not an application of the …
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Does it have something to do with differentiating the integral? No. If what you've posted is all that's in the proof, I understand your confusion----not very enlightening! It's all about continuity. Suppose that there exists a point P(x, …
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Does it have something to do with differentiating the integral? No. If what you've posted is all that's in the proof, I understand your confusion----not very enlightening! It's all about continuity. Suppose that there exists a point P(x, …
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If there's an extremum in the interior of the region, it will occur at a critical point. ∇f = 2x i + (4y - 2) j = <0, 0> ==> x = 0 and y = 1/2. The point (0, 1/2) is inside the circle. On the boundary, f(x, y) = x² + 2y² - 2y…
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If there's an extremum in the interior of the region, it will occur at a critical point. ∇f = 2x i + (4y - 2) j = <0, 0> ==> x = 0 and y = 1/2. The point (0, 1/2) is inside the circle. On the boundary, f(x, y) = x² + 2y² - 2y…
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Does it have something to do with differentiating the integral? No. If what you've posted is all that's in the proof, I understand your confusion----not very enlightening! It's all about continuity. Suppose that there exists a point P(x, …
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Does it have something to do with differentiating the integral? No. If what you've posted is all that's in the proof, I understand your confusion----not very enlightening! It's all about continuity. Suppose that there exists a point P(x, …
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You can solve the first equation for y² in terms of x² (or the other way around) and reduce the system to a quadratic in a single variable. y² = 9 - x². Put this into the second equation x²/64 + (9 - x²)/16 = 1. Multiply through by 64…