neoxow
neoxow
About
- Username
- neoxow
- Joined
- Visits
- 0
- Last Active
- Roles
- Member
Comments
-
(x-4)²-(x-1)²= [(x-4)+(x-1)].[(x-4)-(x-1)] = [2x+3].[0x-3]= -9-6x (x+1)²-(x-2)²= [(x+1)+(x-2)].[(x+1)-(x-2)]= [2x-1].[0x+3]= 6x-3 (2x-1)²+x(3x-2)= 4x² -2.2x.1 + 1+3x²-2x= =7x²-6x+1 x(x-1)²+x²(x+3)= x[(x-1)²+x(x+3)]=x[x²-2.x.1…
-
(x-4)²-(x-1)²= [(x-4)+(x-1)].[(x-4)-(x-1)] = [2x+3].[0x-3]= -9-6x (x+1)²-(x-2)²= [(x+1)+(x-2)].[(x+1)-(x-2)]= [2x-1].[0x+3]= 6x-3 (2x-1)²+x(3x-2)= 4x² -2.2x.1 + 1+3x²-2x= =7x²-6x+1 x(x-1)²+x²(x+3)= x[(x-1)²+x(x+3)]=x[x²-2.x.1…
-
(x-4)²-(x-1)²= [(x-4)+(x-1)].[(x-4)-(x-1)] = [2x+3].[0x-3]= -9-6x (x+1)²-(x-2)²= [(x+1)+(x-2)].[(x+1)-(x-2)]= [2x-1].[0x+3]= 6x-3 (2x-1)²+x(3x-2)= 4x² -2.2x.1 + 1+3x²-2x= =7x²-6x+1 x(x-1)²+x²(x+3)= x[(x-1)²+x(x+3)]=x[x²-2.x.1…