natasha-hunter_60afa97fe3087
natasha-hunter_60afa97fe3087
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4x^2 + 20x +25 product =(25 *4) =a hundred sum= 20 factor = (10,10) ; i.e (10*10=a hundred and 10+10=20) then u destroy the 20x hence 4x^2 + 10x +10x +25 eliminate commons 2x (2x + 5) + 5x (2x + 5) (2x + 5) (2x + 5) this equipment might properly be …