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mroliver

mroliver

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mroliver
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  • 8x2 – 2x – 21=0 Δ= b2-4ac Δ = 4-4x8x(-21)=676 √ Δ = 26 X’ = (-b + √ Δ)/2a = (2+26)/16=28/16=7/4 X” = (-b - √ Δ)/2a = (2-26)/16=-24/16=-3/2
    in como se resolve 2x(4x-1)=21? Comment by mroliver May 2021
  • 8x2 – 2x – 21=0 Δ= b2-4ac Δ = 4-4x8x(-21)=676 √ Δ = 26 X’ = (-b + √ Δ)/2a = (2+26)/16=28/16=7/4 X” = (-b - √ Δ)/2a = (2-26)/16=-24/16=-3/2
    in como se resolve 2x(4x-1)=21? Comment by mroliver May 2021
  • 8x2 – 2x – 21=0 Δ= b2-4ac Δ = 4-4x8x(-21)=676 √ Δ = 26 X’ = (-b + √ Δ)/2a = (2+26)/16=28/16=7/4 X” = (-b - √ Δ)/2a = (2-26)/16=-24/16=-3/2
    in como se resolve 2x(4x-1)=21? Comment by mroliver May 2021

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