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• x ^ 4 - 5 x ^ 2 - 6 y = x ^ 2 y ^ 2 - 5 y - 6 ( y + 1 )( y - 6 ) ( x ^ 2 + 1)( x ^ 2 - 6 ) Solve each of the two factors using quadratic formula, For ( x ^ 2 + 1 ), x = ( 0 +- ( ( 0 ^ 2 ) - 4( 1 )( 1 ) ) ^ 1/2 ) / ( 2( 1 ) ) …

  in how do you factor x^4-5x^2-6? Comment by mred11 June 2021
• x ^ 4 - 5 x ^ 2 - 6 y = x ^ 2 y ^ 2 - 5 y - 6 ( y + 1 )( y - 6 ) ( x ^ 2 + 1)( x ^ 2 - 6 ) Solve each of the two factors using quadratic formula, For ( x ^ 2 + 1 ), x = ( 0 +- ( ( 0 ^ 2 ) - 4( 1 )( 1 ) ) ^ 1/2 ) / ( 2( 1 ) ) …

  in how do you factor x^4-5x^2-6? Comment by mred11 May 2021
• x ^ 4 - 5 x ^ 2 - 6 y = x ^ 2 y ^ 2 - 5 y - 6 ( y + 1 )( y - 6 ) ( x ^ 2 + 1)( x ^ 2 - 6 ) Solve each of the two factors using quadratic formula, For ( x ^ 2 + 1 ), x = ( 0 +- ( ( 0 ^ 2 ) - 4( 1 )( 1 ) ) ^ 1/2 ) / ( 2( 1 ) ) …

  in how do you factor x^4-5x^2-6? Comment by mred11 May 2021
• x ^ 4 - 5 x ^ 2 - 6 y = x ^ 2 y ^ 2 - 5 y - 6 ( y + 1 )( y - 6 ) ( x ^ 2 + 1)( x ^ 2 - 6 ) Solve each of the two factors using quadratic formula, For ( x ^ 2 + 1 ), x = ( 0 +- ( ( 0 ^ 2 ) - 4( 1 )( 1 ) ) ^ 1/2 ) / ( 2( 1 ) ) …

  in how do you factor x^4-5x^2-6? Comment by mred11 May 2021
• x ^ 4 - 5 x ^ 2 - 6 y = x ^ 2 y ^ 2 - 5 y - 6 ( y + 1 )( y - 6 ) ( x ^ 2 + 1)( x ^ 2 - 6 ) Solve each of the two factors using quadratic formula, For ( x ^ 2 + 1 ), x = ( 0 +- ( ( 0 ^ 2 ) - 4( 1 )( 1 ) ) ^ 1/2 ) / ( 2( 1 ) ) …

  in how do you factor x^4-5x^2-6? Comment by mred11 May 2021