meng-tian
meng-tian
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(1) S18 = summation of 3 / (4n^2 + 8n + 3) from n = 2 to n = 19 = summation of (3/2)(1/(2n + 1) - 1/(2n + 3)) from n = 2 to n = 19 = (3/2) * summation of (1 / (2n + 1)) - (1 / (2n + 3)) from n = 2 to n = 19 = (3/2) * [(1/5) - (1/7) + (1/7) - …
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(1) S18 = summation of 3 / (4n^2 + 8n + 3) from n = 2 to n = 19 = summation of (3/2)(1/(2n + 1) - 1/(2n + 3)) from n = 2 to n = 19 = (3/2) * summation of (1 / (2n + 1)) - (1 / (2n + 3)) from n = 2 to n = 19 = (3/2) * [(1/5) - (1/7) + (1/7) - …