mcbengt
mcbengt
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In general it is not possible to solve for A. For example, taking B = I to be the identity matrix, the condition AA^T = I expresses the fact that the columns of A are orthogonal unit vectors (or equivalently that the rows of A are orthogonal unit v…
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It helps to see a concrete case. Suppose P has degree 3 and we call the roots p, q, and r. Then P(z) = (z - p)(z - q)(z - r) and expanding the product on the right hand side and collecting like terms shows you that P(z) = z^3 + (-(p + q + r)) …
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It helps to see a concrete case. Suppose P has degree 3 and we call the roots p, q, and r. Then P(z) = (z - p)(z - q)(z - r) and expanding the product on the right hand side and collecting like terms shows you that P(z) = z^3 + (-(p + q + r)) …
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It helps to see a concrete case. Suppose P has degree 3 and we call the roots p, q, and r. Then P(z) = (z - p)(z - q)(z - r) and expanding the product on the right hand side and collecting like terms shows you that P(z) = z^3 + (-(p + q + r)) …
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In general it is not possible to solve for A. For example, taking B = I to be the identity matrix, the condition AA^T = I expresses the fact that the columns of A are orthogonal unit vectors (or equivalently that the rows of A are orthogonal unit v…
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In general it is not possible to solve for A. For example, taking B = I to be the identity matrix, the condition AA^T = I expresses the fact that the columns of A are orthogonal unit vectors (or equivalently that the rows of A are orthogonal unit v…