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• Carefully. You have to expand the binomial and integrate each term. ((e^x+cos[x])^2) = e^(2x) + 2 e^x cos(x) + [cos(x)]^2. Integrating e^(2x) is straightforward. Integrating 2 e^x cos(x) requires two iterations of integration by parts, plus…

  in how do you integrate ((e^x+cos[x])^2)? Comment by math-prof June 2021