math-h
math-h
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y = mx + c The slope is 2 so, y = 2x + c If it passes through (2, 1): 1 = 2(2) + c c = 1 -4 = -3 So the equation would be y = 2x -3 In standard form: 2x - y = 3
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y = mx + c The slope is 2 so, y = 2x + c If it passes through (2, 1): 1 = 2(2) + c c = 1 -4 = -3 So the equation would be y = 2x -3 In standard form: 2x - y = 3
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Let the longer leg be L The hypotenuse = L + 40 (L + 40)^2 = L^2 + (120^2) L^2 + 80L + 1600 = L^2 + 14400 80L = 14400 - 1600 80L = 12800 L = 12800/80 = 160 meters The length of the longer leg is 160 meters
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Let the longer leg be L The hypotenuse = L + 40 (L + 40)^2 = L^2 + (120^2) L^2 + 80L + 1600 = L^2 + 14400 80L = 14400 - 1600 80L = 12800 L = 12800/80 = 160 meters The length of the longer leg is 160 meters
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y = mx + c The slope is 2 so, y = 2x + c If it passes through (2, 1): 1 = 2(2) + c c = 1 -4 = -3 So the equation would be y = 2x -3 In standard form: 2x - y = 3
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y = mx + c The slope is 2 so, y = 2x + c If it passes through (2, 1): 1 = 2(2) + c c = 1 -4 = -3 So the equation would be y = 2x -3 In standard form: 2x - y = 3
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y = mx + c The slope is 2 so, y = 2x + c If it passes through (2, 1): 1 = 2(2) + c c = 1 -4 = -3 So the equation would be y = 2x -3 In standard form: 2x - y = 3
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y = mx + c The slope is 2 so, y = 2x + c If it passes through (2, 1): 1 = 2(2) + c c = 1 -4 = -3 So the equation would be y = 2x -3 In standard form: 2x - y = 3