martin-campbell_60b1693401f5e
martin-campbell_60b1693401f5e
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(n-2)! =2.(n-4)! <---- vamos passar (n-4)! que esta deste lado a multiplicar para o outro a dividir (n-2)! -------- =2 (n-4)! (n-2)(n-3)(n-4)! --------------------- =2 (n-4)! (n-2)(n-3)=2 n²-3n-2n+6 -2=0 n²-5n+4=0 …