mark-richards_60aefded5437d
mark-richards_60aefded5437d
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- mark-richards_60aefded5437d
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um pouco complicado, mas acho que possa ser assim... __2h___ /_h_____\ 26 área de trapézio = (base maior + base menor) x h / 2 230 = (26+2h) x h / 2 230 = 26h + 2h² / 2 460 = 26h + 2h² à partir daà é resolver a equaÅ