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• x do ponto medio = 2 =( x(A) +x(B) ) = (n + 4)/2 =2--> n= 4 = 4 ---> n = 0 y do ponto medio = 3 = ( y(A) + y(B))/2 = ( m + 5)/2 = 3 ---> m+ 5 = 6 ---> m = 6-5 = 1 logo ( n + m) = 0 + 1 = 1

  in Se (2,3) é ponto médio de AB, com A(n,5) e B(4,m), quanto vale m+n? Comment by logan-phillips_6095ca14ecfb8 May 2021