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• log 16N=-1/2 10^-1/2=16N 16N=1/10^1/2 16N=1/V10 16N=V10/10 4N=(v10/10)/4 4N=V10/40 b) log(base x)(9/4)=1/2 x^1/2=9/4 (x^1/2)²=(9/4)² x=81/16

  in a)se log16 N= -1/2, o valor de 4N é? b) o numero real x, tal que log s (9/4)= 1/2, é? Comment by layla-jones_60b5c2e2e4a0d June 2021