Comments

• I assume you mean the mass is 1.57 * 10^5 kg, which makes a BIG difference. Find the acceleration: s = ut + 0.5at^2 1900 = 0 + 0.5*a*34.5^2 1900 = 595.125a a = 1900 / 595.125 a = 3.19 m/s^2 F = ma F = 1.57 * 10^5 * 3.19 F = 5.01 * 10^5 …

  in Physics forces problem.? Comment by lavalamp3773 June 2021
• Use the quadratic formula: x = ( -b ± √(b^2 - 4ac) ) / 2a x = ( -4 ± √(16 + 56) ) / 2 x = ( -4 ± √(72) ) / 2 x = ( -4 ± 6√(2) ) / 2 x = -2 ± 3√(2) And your two answers are: x = -2 + 3√(2) x = -2 - 3√(2) Which means: p = -2 q…

  in Maths problem A level? Comment by lavalamp3773 June 2021
• Use the quadratic formula: x = ( -b ± √(b^2 - 4ac) ) / 2a x = ( -4 ± √(16 + 56) ) / 2 x = ( -4 ± √(72) ) / 2 x = ( -4 ± 6√(2) ) / 2 x = -2 ± 3√(2) And your two answers are: x = -2 + 3√(2) x = -2 - 3√(2) Which means: p = -2 q…

  in Maths problem A level? Comment by lavalamp3773 June 2021
• Use the quadratic formula: x = ( -b ± √(b^2 - 4ac) ) / 2a x = ( -4 ± √(16 + 56) ) / 2 x = ( -4 ± √(72) ) / 2 x = ( -4 ± 6√(2) ) / 2 x = -2 ± 3√(2) And your two answers are: x = -2 + 3√(2) x = -2 - 3√(2) Which means: p = -2 q…

  in Maths problem A level? Comment by lavalamp3773 May 2021