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kyriakos

kyriakos

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kyriakos
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  • x = original length x-12 = length and width of base 6 = height 6(x-12)(x-12) = 48 x^2 - 24x + 144 = 8 x^2 - 24x +136 = 0 x = (24 +- 4√2)/2 = 12 +- 2√2 B
    in Algebra Word Problem? Comment by kyriakos May 2021
  • x = original length x-12 = length and width of base 6 = height 6(x-12)(x-12) = 48 x^2 - 24x + 144 = 8 x^2 - 24x +136 = 0 x = (24 +- 4√2)/2 = 12 +- 2√2 B
    in Algebra Word Problem? Comment by kyriakos May 2021
  • x = original length x-12 = length and width of base 6 = height 6(x-12)(x-12) = 48 x^2 - 24x + 144 = 8 x^2 - 24x +136 = 0 x = (24 +- 4√2)/2 = 12 +- 2√2 B
    in Algebra Word Problem? Comment by kyriakos May 2021
  • x = original length x-12 = length and width of base 6 = height 6(x-12)(x-12) = 48 x^2 - 24x + 144 = 8 x^2 - 24x +136 = 0 x = (24 +- 4√2)/2 = 12 +- 2√2 B
    in Algebra Word Problem? Comment by kyriakos May 2021
  • x = original length x-12 = length and width of base 6 = height 6(x-12)(x-12) = 48 x^2 - 24x + 144 = 8 x^2 - 24x +136 = 0 x = (24 +- 4√2)/2 = 12 +- 2√2 B
    in Algebra Word Problem? Comment by kyriakos May 2021

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