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kirsty-mason_60bb0636c867d

kirsty-mason_60bb0636c867d

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kirsty-mason_60bb0636c867d
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  • f'(x) = 12x^3 + 12x^2 - 24x Find the critical values by setting f'(x) = 0 and solving. 12x^3 + 12x^2 - 24x = 0 12x(x^2 + x - 2) = 12x((x + 2)(x - 1) = 0 The critical values are x = -2, 0, and 1 (where relative minima or maxima occur). …