kelly-robinson_609d172f14e3a
kelly-robinson_609d172f14e3a
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2^(x+1) + 2^x = 3^(y+2) - 3^y (2^x).2 + (2^x) = (3^y).3² - (3^y), façamos a = 2^x e b = 3^y 2a + a = 9b - b 3a = 8b a = (8/3)b 2^x = 8.3^(y-1) , aplicando logarítimo na base 10, temos: log(2^x) = log[8.3^(y-1)] x.log2 = log[8.3^(y-1)] x = …