kanon86
kanon86
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A= pantalón B= camisa C= corbata D= cinturón tenemos que: A+B+C+D= 1900 A= 2*C B= A+150= 2C+150 D= C-50 sustituyendo (2C)+(2C+150)+C+(C-50)= 1900 reduciendo 6C = 1900 - 150 +50 6C = 1800 Despejando C = 1800/6 C = 300 La co…
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A= pantalón B= camisa C= corbata D= cinturón tenemos que: A+B+C+D= 1900 A= 2*C B= A+150= 2C+150 D= C-50 sustituyendo (2C)+(2C+150)+C+(C-50)= 1900 reduciendo 6C = 1900 - 150 +50 6C = 1800 Despejando C = 1800/6 C = 300 La co…
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A= pantalón B= camisa C= corbata D= cinturón tenemos que: A+B+C+D= 1900 A= 2*C B= A+150= 2C+150 D= C-50 sustituyendo (2C)+(2C+150)+C+(C-50)= 1900 reduciendo 6C = 1900 - 150 +50 6C = 1800 Despejando C = 1800/6 C = 300 La co…