julia-harris_60bb04a0bf8c8
julia-harris_60bb04a0bf8c8
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f'(x) = 12x^3 + 12x^2 - 24x Find the critical values by setting f'(x) = 0 and solving. 12x^3 + 12x^2 - 24x = 0 12x(x^2 + x - 2) = 12x((x + 2)(x - 1) = 0 The critical values are x = -2, 0, and 1 (where relative minima or maxima occur). …