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• Considera-se x²=y y²-y-12=0 Δ=b²-4ac Δ=(-1)²-4*1*(-12) Δ=1+48 Δ=49 Bhaskara y=-b±√Δ/2a y=-(-1)±√49/2*1 y= 1±7/2 y´=1+7/2 y´= 8/2 = 4 y´´=1-7/2 y´´= -6/2 = -3 Como x²= y, temos: x²= 4 x=±√4 x=±2…

  in quem me ajuda D) x⁴-x²= 12? Comment by john-marshall_60c2f19e19ec0 June 2021