jayden-young_60bd78db34d88
jayden-young_60bd78db34d88
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Vamos lá: 3X² - 10X + 5 = 0 ∆ = b²-4.a.c ∆ = (-10)² - 4*(3)*(5) ∆ = 100 - 60 ∆ = 40 X = ( -b ± √∆ ) / 2*a X = ( 10 ± √40 ) / 2*(3) = ( 10 ± √40 ) / 6 então x' = ( 10 + √40 ) / 6 = (5+√10)/3 x'' = ( 10 - √40 ) / 6 = (5-√10)/3…