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jammy

jammy

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jammy
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  • factorize the denominator of the first fraction 3/(x+1)(x+3) - 1/(x+3)(x-3) = [3(x-3)-(x+1)]/[(x+1)(x-3)(x+3)] = (2x-10)/ (x^3+x^2-9x-9)
    in Algebra?????????????? Comment by jammy May 2021
  • factorize the denominator of the first fraction 3/(x+1)(x+3) - 1/(x+3)(x-3) = [3(x-3)-(x+1)]/[(x+1)(x-3)(x+3)] = (2x-10)/ (x^3+x^2-9x-9)
    in Algebra?????????????? Comment by jammy May 2021
  • factorize the denominator of the first fraction 3/(x+1)(x+3) - 1/(x+3)(x-3) = [3(x-3)-(x+1)]/[(x+1)(x-3)(x+3)] = (2x-10)/ (x^3+x^2-9x-9)
    in Algebra?????????????? Comment by jammy May 2021