imogen-thomas_60966c241970e
imogen-thomas_60966c241970e
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Molar mass of copper(II) bicarbonate = 63.5 + 2*(1 + 12 + 3*16) g mol^-1 = 185.5 g mol^-1 Now, 1 mole of Cu(HCO3)2 = 185.5 g Therefore, 1.28 moles = 237.44 g was produced