helen-wilkinson_609d03343b303
helen-wilkinson_609d03343b303
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3^(4√x) - 4*3^(√4x) + 3 = 0 3^(4√x) - 4*3^(2√x) + 3 = 0 [3^(2√x)]² - 4*3^(2√x) + 3 = 0 -> façamos a = 3^(2√x) a² - 4a + 3 = 0 a' = 1 e a'' = 3 Para a = 1: 1 = 3^(2√x) = 3º 2√x = 0 x = 0 Para a = 3: 3 = 3^(2√x)= 3¹ 2√x = 1 √x = 1/…