Comments

• first rearrange to get the sq. root on my own so root (3x+a million) = (x-a million) to get rid of the sq. root, sq. the two facets so ( (sq. root of 3x+a million) ) ^ 2 = 3x + a million so 3x+a million = (x-a million)^2 then 3x + a million = x^2 -2…

  in Math problem! 1/x? 1/1/x? Comment by hagensee June 2021
• first rearrange to get the sq. root on my own so root (3x+a million) = (x-a million) to get rid of the sq. root, sq. the two facets so ( (sq. root of 3x+a million) ) ^ 2 = 3x + a million so 3x+a million = (x-a million)^2 then 3x + a million = x^2 -2…

  in Math problem! 1/x? 1/1/x? Comment by hagensee May 2021