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gokulkarandikar

gokulkarandikar

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gokulkarandikar
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  • Its too easy. 8x^2 - 2x - 3 = 0 => 8x^2 - 4x + 6x - 3 = 0 => 4x(2x - 1) + 3(2x - 1) => (4x + 3) (2x - 1) => 4x + 3 = 0 or 2x - 1 = 0 => x = -3/4 or x = 1/2 I hope it is helpful. If u need any help in maths, contact me @ goku…
  • Its too easy. 8x^2 - 2x - 3 = 0 => 8x^2 - 4x + 6x - 3 = 0 => 4x(2x - 1) + 3(2x - 1) => (4x + 3) (2x - 1) => 4x + 3 = 0 or 2x - 1 = 0 => x = -3/4 or x = 1/2 I hope it is helpful. If u need any help in maths, contact me @ goku…
  • Its too easy. 8x^2 - 2x - 3 = 0 => 8x^2 - 4x + 6x - 3 = 0 => 4x(2x - 1) + 3(2x - 1) => (4x + 3) (2x - 1) => 4x + 3 = 0 or 2x - 1 = 0 => x = -3/4 or x = 1/2 I hope it is helpful. If u need any help in maths, contact me @ goku…
  • Its too easy. 8x^2 - 2x - 3 = 0 => 8x^2 - 4x + 6x - 3 = 0 => 4x(2x - 1) + 3(2x - 1) => (4x + 3) (2x - 1) => 4x + 3 = 0 or 2x - 1 = 0 => x = -3/4 or x = 1/2 I hope it is helpful. If u need any help in maths, contact me @ goku…