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• Slope of the perpendicular line to the tangent given = - 1/6 Equation of the perpendicular line that goes through (3,9) y-9 = (-1/6)(x-3) 6y-54 = -x + 3 6y+x-57=0 Now solve this line & parabola for intersection points Then, x^2 = (57-x)/…

  in Help with parabola problem? Comment by geeganage-w June 2021
• Slope of the perpendicular line to the tangent given = - 1/6 Equation of the perpendicular line that goes through (3,9) y-9 = (-1/6)(x-3) 6y-54 = -x + 3 6y+x-57=0 Now solve this line & parabola for intersection points Then, x^2 = (57-x)/…

  in Help with parabola problem? Comment by geeganage-w June 2021