fred-lewis_60c2230985db0
fred-lewis_60c2230985db0
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vamos la se os retangulo tem areas iguais entao (5x-1)2x= (3x+6)(x+1) 10x²-2x= 3x²+3x+6x+6 7x²-11x-6= 0 delta= 121+168= 289 x=(11+-17)/14 x= -6/14 descartada essa solução pq x e medida e tem que ser positivo okkk x''= 28/14 = 2 retangul…