fcas80
fcas80
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Get at least a master's
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R(x) = -20x^2 + 1000x R'(x) = -40x + 1000; critical point at x=25. If x<25 R' >0, and if x>25 R'<0. R'(x)=0 at x=25, which provides max revenue. Max rev = -20*(25^2)+1000*25=12500
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R(x) = -20x^2 + 1000x R'(x) = -40x + 1000; critical point at x=25. If x<25 R' >0, and if x>25 R'<0. R'(x)=0 at x=25, which provides max revenue. Max rev = -20*(25^2)+1000*25=12500
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(2/3)N - 4 = (5/3)N -4 = (3/3)N N = -4
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If you can not research the Georgia State website to find out, then you should not think about going there - it will be too hard for you.
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(x+3) ^(2/3) = 8 (x+3) ^[(2/3)(3/2)] = 8^(3/2) (x+3) = (8*8*8)^(1/2) = 512^(1/2) = (256*2)^(1/2) = 16*(2^(1/2)) (x+3) = 16*(2^(1/2)) x = 16*(2^(1/2)) - 3 Note that x=1 does not satisfy the original equation.
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(x+3) ^(2/3) = 8 (x+3) ^[(2/3)(3/2)] = 8^(3/2) (x+3) = (8*8*8)^(1/2) = 512^(1/2) = (256*2)^(1/2) = 16*(2^(1/2)) (x+3) = 16*(2^(1/2)) x = 16*(2^(1/2)) - 3 Note that x=1 does not satisfy the original equation.
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Competitive for admissions? No, they will admit practically anyone.
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Competitive for admissions? No, they will admit practically anyone.
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Competitive for admissions? No, they will admit practically anyone.
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(x+3) ^(2/3) = 8 (x+3) ^[(2/3)(3/2)] = 8^(3/2) (x+3) = (8*8*8)^(1/2) = 512^(1/2) = (256*2)^(1/2) = 16*(2^(1/2)) (x+3) = 16*(2^(1/2)) x = 16*(2^(1/2)) - 3 Note that x=1 does not satisfy the original equation.
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If you can not research the Georgia State website to find out, then you should not think about going there - it will be too hard for you.
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If you can not research the Georgia State website to find out, then you should not think about going there - it will be too hard for you.
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If you can not research the Georgia State website to find out, then you should not think about going there - it will be too hard for you.
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(2/3)N - 4 = (5/3)N -4 = (3/3)N N = -4
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R(x) = -20x^2 + 1000x R'(x) = -40x + 1000; critical point at x=25. If x<25 R' >0, and if x>25 R'<0. R'(x)=0 at x=25, which provides max revenue. Max rev = -20*(25^2)+1000*25=12500