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• cot^2x+cos-csc x cot x=(cos x)/(1+sec x)? l.h.s. = cot^2x+cos-csc x cot x = cos^2x/sin^2x +cosx -cosx/sin^2x = = (cos^2x +cosx.sin^2x -cosx)/sin^2x = cosx(cosx +sin^2x-1)/sin^2x = = cosx(cosx - cos^2x)/sin^2x = (cos x)/(1+sec x) = R.H.S…

  in how to verify cot^2x+cos-csc x cot x=(cos x)/(1+sec x)? Comment by fazaldin-a June 2021
• (1) / ( ³√(x^2) = 1 / x^(2/3) = x^(-2/3) >===================< ANSWER

  in Write (1) / ( ³√(x^2) as x to some power? Comment by fazaldin-a June 2021
• (1) / ( ³√(x^2) = 1 / x^(2/3) = x^(-2/3) >===================< ANSWER

  in Write (1) / ( ³√(x^2) as x to some power? Comment by fazaldin-a June 2021
• cos3x = 4cos^3 x - 3cosx? L.H.S. = cos3x = cos(2x+x) = cos2x.cosx - sin2x.sinx L.H.S. = (2cos^2x -1)cosx - 2sinx.cosx.sinx L.H.S. = 2cos^3x -cosx - 2(1-cos^2x)cosx L.H.S. = 2cos^3x -cosx -2cosx + 2cos^3x L.H.S. = 4cos^3x - 3cosx = R.H.…

  in Verify: cos3x = 4cos^3 x - 3cosx? Comment by fazaldin-a June 2021
• Statement "D). PT + TQ = PQ " is Not appropriate. >===< ANSWER

  in Math problem? Comment by fazaldin-a June 2021
• Statement "D). PT + TQ = PQ " is Not appropriate. >===< ANSWER

  in Math problem? Comment by fazaldin-a June 2021
• Derivative of y=cos(e^(-3x))? y' = -sin(e^(-3x))*(e^(-3x))*(-3) y' = +3(e^-3x)*sin(e^(-3x)) >==============< ANSWER

  in Derivative of y=cos(e^(-3x))? Comment by fazaldin-a June 2021
• Derivative of y=cos(e^(-3x))? y' = -sin(e^(-3x))*(e^(-3x))*(-3) y' = +3(e^-3x)*sin(e^(-3x)) >==============< ANSWER

  in Derivative of y=cos(e^(-3x))? Comment by fazaldin-a June 2021
• Y = sqrtx (3x-1) dy/dx = 3 / 2*sqrt(3x-1) >===========< ANSWER SO, Answer is : B) 3/2sqrt(x-1) Answer is :

  in How do you solve this derivative problem? Comment by fazaldin-a June 2021
• -20+5x = 6x+(1/5) 5X -6X = 1/5 +20, ===> -x = 101/5 = 20.2 OR, x = -20.2 >=================================< ANSWER

  in basic algebra problem help? Comment by fazaldin-a May 2021
• [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ] = = 6/(x+3) -2(x-1)(x-1)/x -3/(x+2) = 6/(x+3) -2(x-1)^2/x -3/(x+2) = = 6/(x+3) -2(x-1)^2/x -3/(x+2) >=================< ANSWER

  in algebra problem [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]? Comment by fazaldin-a May 2021
• [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ] = = 6/(x+3) -2(x-1)(x-1)/x -3/(x+2) = 6/(x+3) -2(x-1)^2/x -3/(x+2) = = 6/(x+3) -2(x-1)^2/x -3/(x+2) >=================< ANSWER

  in algebra problem [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]? Comment by fazaldin-a May 2021
• [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ] = = 6/(x+3) -2(x-1)(x-1)/x -3/(x+2) = 6/(x+3) -2(x-1)^2/x -3/(x+2) = = 6/(x+3) -2(x-1)^2/x -3/(x+2) >=================< ANSWER

  in algebra problem [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]? Comment by fazaldin-a May 2021
• Here we have, Heat energy = 5.0 x 102 J efficiency = 28 % Let Total Energy = E, Then 5.0 x 102 x 100 / E = 28 E = 5.0 x 102 x 100 / 28 = 1821.43 J .................. Answer

  in how do i do this physicsproblem? Comment by fazaldin-a May 2021
• Here we have, Heat energy = 5.0 x 102 J efficiency = 28 % Let Total Energy = E, Then 5.0 x 102 x 100 / E = 28 E = 5.0 x 102 x 100 / 28 = 1821.43 J .................. Answer

  in how do i do this physicsproblem? Comment by fazaldin-a May 2021
• [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ] = = 6/(x+3) -2(x-1)(x-1)/x -3/(x+2) = 6/(x+3) -2(x-1)^2/x -3/(x+2) = = 6/(x+3) -2(x-1)^2/x -3/(x+2) >=================< ANSWER

  in algebra problem [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]? Comment by fazaldin-a May 2021
• [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ] = = 6/(x+3) -2(x-1)(x-1)/x -3/(x+2) = 6/(x+3) -2(x-1)^2/x -3/(x+2) = = 6/(x+3) -2(x-1)^2/x -3/(x+2) >=================< ANSWER

  in algebra problem [ 6(x+3)^-1 - 2(x-1) / x(x-1)^-1 - 3(x+2)^-1 ]? Comment by fazaldin-a May 2021
• -20+5x = 6x+(1/5) 5X -6X = 1/5 +20, ===> -x = 101/5 = 20.2 OR, x = -20.2 >=================================< ANSWER

  in basic algebra problem help? Comment by fazaldin-a May 2021
• -20+5x = 6x+(1/5) 5X -6X = 1/5 +20, ===> -x = 101/5 = 20.2 OR, x = -20.2 >=================================< ANSWER

  in basic algebra problem help? Comment by fazaldin-a May 2021
• -20+5x = 6x+(1/5) 5X -6X = 1/5 +20, ===> -x = 101/5 = 20.2 OR, x = -20.2 >=================================< ANSWER

  in basic algebra problem help? Comment by fazaldin-a May 2021
• -20+5x = 6x+(1/5) 5X -6X = 1/5 +20, ===> -x = 101/5 = 20.2 OR, x = -20.2 >=================================< ANSWER

  in basic algebra problem help? Comment by fazaldin-a May 2021
• -20+5x = 6x+(1/5) 5X -6X = 1/5 +20, ===> -x = 101/5 = 20.2 OR, x = -20.2 >=================================< ANSWER

  in basic algebra problem help? Comment by fazaldin-a May 2021
• Y = sqrtx (3x-1) dy/dx = 3 / 2*sqrt(3x-1) >===========< ANSWER SO, Answer is : B) 3/2sqrt(x-1) Answer is :

  in How do you solve this derivative problem? Comment by fazaldin-a May 2021
• Y = sqrtx (3x-1) dy/dx = 3 / 2*sqrt(3x-1) >===========< ANSWER SO, Answer is : B) 3/2sqrt(x-1) Answer is :

  in How do you solve this derivative problem? Comment by fazaldin-a May 2021
• Derivative of y=cos(e^(-3x))? y' = -sin(e^(-3x))*(e^(-3x))*(-3) y' = +3(e^-3x)*sin(e^(-3x)) >==============< ANSWER

  in Derivative of y=cos(e^(-3x))? Comment by fazaldin-a May 2021
• Statement "D). PT + TQ = PQ " is Not appropriate. >===< ANSWER

  in Math problem? Comment by fazaldin-a May 2021
• Statement "D). PT + TQ = PQ " is Not appropriate. >===< ANSWER

  in Math problem? Comment by fazaldin-a May 2021
• cos3x = 4cos^3 x - 3cosx? L.H.S. = cos3x = cos(2x+x) = cos2x.cosx - sin2x.sinx L.H.S. = (2cos^2x -1)cosx - 2sinx.cosx.sinx L.H.S. = 2cos^3x -cosx - 2(1-cos^2x)cosx L.H.S. = 2cos^3x -cosx -2cosx + 2cos^3x L.H.S. = 4cos^3x - 3cosx = R.H.…

  in Verify: cos3x = 4cos^3 x - 3cosx? Comment by fazaldin-a May 2021