Comments

• considera un rettangolo ABCD. p=2AB+2BC=31.6 cm AB-BC=9,4 cm ->AB=9.4cm+BC sostituendo: 2(9.4cm+BC)+2BC=31.6 cm 18.8cm+2BC+2BC=31.6 cm 4BC=12.8cm BC=3.2 cm AB=9.4+BC=9.4+3.2=12.6 Teorema di pitagora: DB^2=AB^2+BC^2=169cm -> DB=13 cm

  in ragazzi aiuto problema geometria...? Comment by ether-dale June 2021
• considera un rettangolo ABCD. p=2AB+2BC=31.6 cm AB-BC=9,4 cm ->AB=9.4cm+BC sostituendo: 2(9.4cm+BC)+2BC=31.6 cm 18.8cm+2BC+2BC=31.6 cm 4BC=12.8cm BC=3.2 cm AB=9.4+BC=9.4+3.2=12.6 Teorema di pitagora: DB^2=AB^2+BC^2=169cm -> DB=13 cm

  in ragazzi aiuto problema geometria...? Comment by ether-dale May 2021