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ellie-walsh_60aa1b696f822

ellie-walsh_60aa1b696f822

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ellie-walsh_60aa1b696f822
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  • se P(x)=2b²x-bx³ e Q(x)= a³x+ 2ax² então P(a)=2b²a - ba³ e Q(b)= a³b + 2ab² P(a)-Q(b)= 2b²a - ba³ - (a³b+ 2ab²)= 2b²a- ba³ - a³b - 2ab²= P(a)-Q(b)= 2b²a - 2b²a - ba³ - a³b= P(a)-Q(b)= 0 -ba³ -ba³ = -2ba³ Resposta: P(a)-Q(b)= …