Comments

• cosx(2cosx-1)=0 cosx=0 or 2cosx-1=0 x=(2m+1)pi/2 or cosx=1/2 x=2npi+pi/3,2npi-pi/3

  in 2cos^2(x) - cos(x) = 0? Comment by dupinder-jeet-kaur-k June 2021
• cosx(2cosx-1)=0 cosx=0 or 2cosx-1=0 x=(2m+1)pi/2 or cosx=1/2 x=2npi+pi/3,2npi-pi/3

  in 2cos^2(x) - cos(x) = 0? Comment by dupinder-jeet-kaur-k June 2021
• cosx(2cosx-1)=0 cosx=0 or 2cosx-1=0 x=(2m+1)pi/2 or cosx=1/2 x=2npi+pi/3,2npi-pi/3

  in 2cos^2(x) - cos(x) = 0? Comment by dupinder-jeet-kaur-k May 2021
• cosx(2cosx-1)=0 cosx=0 or 2cosx-1=0 x=(2m+1)pi/2 or cosx=1/2 x=2npi+pi/3,2npi-pi/3

  in 2cos^2(x) - cos(x) = 0? Comment by dupinder-jeet-kaur-k May 2021