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dnaunion

dnaunion

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dnaunion
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  • c)0.30mg 3 half lifes have elapsed: elapsed time / half life = elapsed half lives 17190 / 5730 = 3 Each half life cuts in half the amount of C-14 remaining. 3 half lives have passed, so there is now (1/2)^3 = 1/8 as much C-14 as there init…
  • a)made directly from DNA during transcription One could bicker about tRNA beind made directly from DNA, since the primary transcript of tRNA is processed, but that's a nitpick -- all the others are just clearly wrong.
  • a)made directly from DNA during transcription One could bicker about tRNA beind made directly from DNA, since the primary transcript of tRNA is processed, but that's a nitpick -- all the others are just clearly wrong.
  • Another thing that being double stranded does is allow for error checking and correction. Certain enzymes can detect mismatched bases, where the base in one strand is not complementary to the base in the other strand. This information allows the…
  • Another thing that being double stranded does is allow for error checking and correction. Certain enzymes can detect mismatched bases, where the base in one strand is not complementary to the base in the other strand. This information allows the…
  • Another thing that being double stranded does is allow for error checking and correction. Certain enzymes can detect mismatched bases, where the base in one strand is not complementary to the base in the other strand. This information allows the…
  • a)made directly from DNA during transcription One could bicker about tRNA beind made directly from DNA, since the primary transcript of tRNA is processed, but that's a nitpick -- all the others are just clearly wrong.
  • a)made directly from DNA during transcription One could bicker about tRNA beind made directly from DNA, since the primary transcript of tRNA is processed, but that's a nitpick -- all the others are just clearly wrong.
  • c)0.30mg 3 half lifes have elapsed: elapsed time / half life = elapsed half lives 17190 / 5730 = 3 Each half life cuts in half the amount of C-14 remaining. 3 half lives have passed, so there is now (1/2)^3 = 1/8 as much C-14 as there init…
  • c)0.30mg 3 half lifes have elapsed: elapsed time / half life = elapsed half lives 17190 / 5730 = 3 Each half life cuts in half the amount of C-14 remaining. 3 half lives have passed, so there is now (1/2)^3 = 1/8 as much C-14 as there init…
  • c)0.30mg 3 half lifes have elapsed: elapsed time / half life = elapsed half lives 17190 / 5730 = 3 Each half life cuts in half the amount of C-14 remaining. 3 half lives have passed, so there is now (1/2)^3 = 1/8 as much C-14 as there init…
  • c)0.30mg 3 half lifes have elapsed: elapsed time / half life = elapsed half lives 17190 / 5730 = 3 Each half life cuts in half the amount of C-14 remaining. 3 half lives have passed, so there is now (1/2)^3 = 1/8 as much C-14 as there init…
  • c)0.30mg 3 half lifes have elapsed: elapsed time / half life = elapsed half lives 17190 / 5730 = 3 Each half life cuts in half the amount of C-14 remaining. 3 half lives have passed, so there is now (1/2)^3 = 1/8 as much C-14 as there init…