dawonzcher
dawonzcher
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How to do this algebraic problem? 3/4x−1/2=1/2x+1 Solve for x: 3/4x−1/2=1/2x+1 <== transpose variable to the left, constants to the right. 3/4 x - 1/2 x = 1 + 1/2 3/4 x - 2/4 x = 2/2 + 1/2 <== 1/2 x = 1/2(2/2)x = 2/4 x, and 1(2/2) =…
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How to do this algebraic problem? 3/4x−1/2=1/2x+1 Solve for x: 3/4x−1/2=1/2x+1 <== transpose variable to the left, constants to the right. 3/4 x - 1/2 x = 1 + 1/2 3/4 x - 2/4 x = 2/2 + 1/2 <== 1/2 x = 1/2(2/2)x = 2/4 x, and 1(2/2) =…
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Let: A= 80 degrees a= ? b=6 ft c= 9 ft Solve for side "a" using Cosine Law: a^2 = b^2 + c^2 -2bcCosA a= sqrt[6^2 + 9^2 - 2(6)(9)Cos80] a = sqrt(117 - 18.754) a= 9.91 ft You can use Hero's formula to directly get the area of …
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Let: A= 80 degrees a= ? b=6 ft c= 9 ft Solve for side "a" using Cosine Law: a^2 = b^2 + c^2 -2bcCosA a= sqrt[6^2 + 9^2 - 2(6)(9)Cos80] a = sqrt(117 - 18.754) a= 9.91 ft You can use Hero's formula to directly get the area of …
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Let: A= 80 degrees a= ? b=6 ft c= 9 ft Solve for side "a" using Cosine Law: a^2 = b^2 + c^2 -2bcCosA a= sqrt[6^2 + 9^2 - 2(6)(9)Cos80] a = sqrt(117 - 18.754) a= 9.91 ft You can use Hero's formula to directly get the area of …
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Let: A= 80 degrees a= ? b=6 ft c= 9 ft Solve for side "a" using Cosine Law: a^2 = b^2 + c^2 -2bcCosA a= sqrt[6^2 + 9^2 - 2(6)(9)Cos80] a = sqrt(117 - 18.754) a= 9.91 ft You can use Hero's formula to directly get the area of …
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Let: A= 80 degrees a= ? b=6 ft c= 9 ft Solve for side "a" using Cosine Law: a^2 = b^2 + c^2 -2bcCosA a= sqrt[6^2 + 9^2 - 2(6)(9)Cos80] a = sqrt(117 - 18.754) a= 9.91 ft You can use Hero's formula to directly get the area of …