darren-graham_60b5e75767aba
darren-graham_60b5e75767aba
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First we can divide a little bit: ...x²:(x-1) = x+1+(1/(x-1)) -(x²-x) -------- .......x .....-(x-1) ------------ ...........1 .........-1 ------------ ...........0 Now 0.5................0.5 ..∫x²:(x-1)dx = ∫x+1+(1/(x-1))]dx -1...…