danielle-palmer_60b055ff473c6
danielle-palmer_60b055ff473c6
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Soma de uma PA de n termos = (a₁+ an)*r/2 (a₁ + an)*9/2 = 0 (a₁ + an)*9 = 0 a₁ + an = 0 Sabemos que an = a₁ + r(n - 1), então: a₁ + a₁ + r(n - 1) = 0 2a₁ + 2(9 - 1) = 0 2a₁ + 16 = 0 a₁ = -8 O sexto termo é, então: a6 = -8 + 2(6 - 1) = -…