Comments

• using the laws of logs, by adding them, you can multiply what you have in the brackets to get: ln((x-3)(x+3)) = ln(x^2 - 9) a

  in express a single natural log: ln(x-3)+ln(x+3)? Comment by danelius90 May 2021
• using the laws of logs, by adding them, you can multiply what you have in the brackets to get: ln((x-3)(x+3)) = ln(x^2 - 9) a

  in express a single natural log: ln(x-3)+ln(x+3)? Comment by danelius90 May 2021
• using the laws of logs, by adding them, you can multiply what you have in the brackets to get: ln((x-3)(x+3)) = ln(x^2 - 9) a

  in express a single natural log: ln(x-3)+ln(x+3)? Comment by danelius90 May 2021
• using the laws of logs, by adding them, you can multiply what you have in the brackets to get: ln((x-3)(x+3)) = ln(x^2 - 9) a

  in express a single natural log: ln(x-3)+ln(x+3)? Comment by danelius90 May 2021