daisy-lee_60a4d1fc7e1b2
daisy-lee_60a4d1fc7e1b2
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Ok, veja como resolver, I= ʃ (cos³x / sen⁴x) dx = ʃ [(cos³x / sen³x)∙(1/sen x)] dx = ʃ cotg³x∙cossecx dx = ʃ cotg²x∙cotgx∙cossecx dx = ʃ (cossec²x - 1)∙cotgx∙cossecx dx ~~ > pois cotg²x = cossec²x -1 = ʃ cossec²x∙cotgx∙cossecx d…